Question

The age of a father is five time that of his son. two years before he was three more than six times his sons age.find their present age

Answer 1

Answer:

son's present age = 7 years

father's present age = 35 years

Step-by-step explanation:

let father's age be x

let son's age be y

father is 5 times that of son's age

x = 5y

two years ago father was 3 more than six times his sons age

x - 2 = 6(y-2) + 3

x - 2 = 6y - 12 + 3

x - 2 = 6y - 9

x - 6y = -9 + 2

x - 6y = -7

substitute x = 5y

5y - 6y = -7

-y = -7

y = 7

son's present age is 7

x = 5y

x = 5 × 7

x = 35

father's age = 35

hope you get your answer