Question

The age of a father is four times the age of his son. Five years hence, the age of
father will be three times the age of his son. Find their present ages

Answer 1

Answer:

let the age of son be x .

let the age of father be 4x

after 5 years son's age = x + 5

after 5 years father's age = 4x + 5

4x + 5 = 3 ( x + 5 )

4x + 5 = 3x + 15

4x - 3x = 15 - 5

x = 10

therefore,

age of son = 10 years

age of father = 4 × 10 = 40 years

Answer 2

Step-by-step explanation:

let x be the age of the son

therefore father's age = 4x

After 5 years

4x+5= 3 (x+5)

4x+5= 3x+15

4x-3x= 15-5

x= 10

father's age= 4x= 40

their present ages are 10 and 40