The age of a father is six times the age of his son. twenty years from now, father's age will be twice as old as son's age. what is the father's present age ? (in years)
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Age of father = x years
Age of his son = Y years
x = 6y. ............(1)
x + 20 = 2(Y + 20)
x + 20 = 2y + 40
x - 2y + 20 - 40 = 0
x - 2y - 20 = 0
6y - 2y = 20. .......(from eq. (1))
4y = 20
Y = 5
put value of (Y) in eq. (1).....
so we get,
x = 6(5)
x = 30
Age of father is 30 years
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☺ HOPE IT HELPS YOU
======================================
Age of father = x years
Age of his son = Y years
x = 6y. ............(1)
x + 20 = 2(Y + 20)
x + 20 = 2y + 40
x - 2y + 20 - 40 = 0
x - 2y - 20 = 0
6y - 2y = 20. .......(from eq. (1))
4y = 20
Y = 5
put value of (Y) in eq. (1).....
so we get,
x = 6(5)
x = 30
Age of father is 30 years
=========================================
☺ HOPE IT HELPS YOU
Answered by
2
well i hope u understand.......................
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