Math, asked by saprakiran70, 1 year ago

The age of a father is three times of his son. 5 years ago father was five times as old as his son. Find their present ages.

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Answered by Anonymous
3

Answer:

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Answered by Anonymous
15

• Let present age of son be M.

» The age of a father is three times of his son.

• Age of father = 3M

» 5 years ago

• Age of son = M - 5

• Age of father = 3M - 5

» 5 years ago father was five times as old as his son.

A.T.Q.

=> 3M - 5 = 5(M - 5)

=> 3M - 5 = 5M - 25

=> 3M - 5M = - 25 + 5

=> - 2M = - 20

=> 2M = 20

=> M = 10

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\textbf{Present age of son = M = 10 years.}

\textbf{Present age of father = 3M = 3(10)}

\textbf{= 30 years}

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