the age of A
is 5 years more than that of B 5 years ago the ratio of their ages was 3 ratio to find the present ages
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Let the present age of B be x
Present age of A = x + 5
According to question,
( x + 5 - 5) / (x - 5) = 3 /2
=> ( x ) / (x - 5) = 3 /2
=> 2x = 3x - 15
=> 3x - 2x = 15
=> x = 15
Present age of B = 15 years
Present age of A = 20 years
Present age of A = x + 5
According to question,
( x + 5 - 5) / (x - 5) = 3 /2
=> ( x ) / (x - 5) = 3 /2
=> 2x = 3x - 15
=> 3x - 2x = 15
=> x = 15
Present age of B = 15 years
Present age of A = 20 years
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if 15 and 20 is right answer then 5 years before ages will b 10 and 15 and even a nursery student knows 10 and 15 are not in the ratio of 3
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