Math, asked by varsharana1, 1 year ago

the age of A is 5 years more than the age of B five year ago . the ratio of their age was 3:2 . find their present ages.

Answers

Answered by prajwaldj
12
let age of B be x
equation=

Age of B = X

Age of A= X+5

5 years ag , the ratio was 2:3 ( I reversed the ratio cuz I took B first)

2/3 = X/X+5

Now by cross multiplying

2(X+5)=3X

=> 2X + 10 = 3X

=> X = 10


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Answered by Anonymous
19
HEYA FRIEND ☺

HERE IS YOUR ANSWER

Let the age of B be x

Then the age of A = x+5

FIVE YEARS AGO :
______________

A's age=x+5-5=x

B's age=x-5

===============================

Ratio of their ages :

x/(x-5)=3/2

2x=3(x-5)

2x=3x-15

15=3x-2x

x=15

===============================

THEIR PRESENT AGE :
_________________


AGE OF B = 15 years

AGE OF A= x+5=15+5=20 years

===============================

HOPE THIS HELPS YOU

Aashchawla: Hello
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