Question

The age of A is 5 years more than the age of B. Five years ago, the age of their ratios was 3:2. Find their present ages. ​

Answer 1

Answer:

Step-by-step explanation:

Let The present age of B be X years.

Then the age of A = ( X + 5) years.

Before Five years age of A = ( X +5 - 5) = X years.

Before Five years age of B = ( X -5) years.

According to question ,

A : B = 3:2

X / X -5 = 3/2

2 ( X )= 3 ( X -5)

2X = 3X -15

3X - 2X = 15

X = 15 years.

Present age of B = X = 15 years

And,

Present age of A = X +5 = 15+5 = 20 years.

Answer 2

Solution:

Let the age of B is x

And A is (x+5)

Five years ago, B=x-5

ㅤㅤㅤㅤㅤㅤㅤA=x+5-5=x

• 5 and - 5 will cut out

⇢$\sf \dfrac{A}{B}$=$\sf \dfrac{3}{2}$=$\sf \dfrac{x}{x-5}$

• Cross multiplication

⇢(x-5)3=x(2)

⇢3x-15=2x

⇢x=15

Hence present age of A is $\sf \pink{15 \ years}$

Present age of B is x+5

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ=15+5

ㅤㅤㅤㅤㅤㅤㅤ⇢$\sf \pink{20 \ years}$