The age of A is five years more than that of B. 5 years ago the ratio of their ages was 3:2 . Find their present ages
Answers
Answered by
12
✬ A's age = 20 Years ✬
✬ B's age = 15 Years ✬
Step-by-step explanation:
Given:
- Age of A is five years more that B's age.
- 5 years ago the ratio of their ages was 3:2.
To Find:
- What is their present ages ?
Solution: Let the age of B be x years. Therefore
➼ A's age = 5 years more than B's age.
➼ A's age = (x + 5) years.
Now, 5 years ago their ages was:-
- B's age = (x – 5) Years
- A's age = (x + 5 – 5) = (x) Years.
A/q
- Five years age the ratio of their ages will 3 : 2
(A's age) : (B's age) = 3 : 2
(x) / (x – 5) = 3/2
2(x) = 3(x – 5)
2x = 3x – 15
2x – 3x = – 15
– x = – 15
x = 15
Hence,
➟ Age of B = x = 15 years
➟ Age of A = (x + 5) = 15+5 = 20 years
Answered by
9
GIVEN:
- The age of A is five years more than that of B
- 5 years ago the ratio of their ages was 3:2
TO FIND:
- What are their presence ages ?
SOLUTION:
Let the age of A be 'p' years and that of B be 'q' years
Case:- ❶
☛ The age of A is five years more than that of B
Case:- ❷
☛ 5 years ago the ratio of their ages was 3:2
- A's age = (p - 5) years
- B's age = (q - 5) years
According to question:-
Put the value of 'p' from equation 1)
Put the value of 'q' in equation 1)
- A's age = p = 20 years
- B's age = q = 15 years
❝ Hence, the present ages of A and B are 20 years and 15 years respectively. ❞
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