Math, asked by karansoni781, 1 year ago

the age of A is five years more than that of B. 5 years ago, the ratio of their ages was 3:2. find their present age?​

Answers

Answered by TheLostMonk
3

Answer:

20,15

Step-by-step explanation:

let B = x then A = x + 5

5 years ago

(x+5 - 5)/(x - 5) = 3/ 2

2x = 3x - 15 => x = 15

A = 15+5 = 20 yr & B = 15 yr

Answered by joshimanoj578
1

Answer:

Step-by-step explanation:

let the age of B be x years

Hence the age of A will be x+5 years

Five years ago

x+5 : x = 3 : 2 ............(since the difference between between ages remains same)

By cross multiplication

2x + 10 =3x

10= 3x - 2x = x

Hence 5 years ago age of B was 10 years

Present age of B = 10+5= 15 years

Present age of A =15+5=20 years

Hence age of A is 20 years & B is 15 years

I hope this will help you..

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