Math, asked by sahusoumyaranjan616, 7 hours ago

The age of A is five years more than that of B. 5 years ago, the ratio of their ages was 3:2. Find their present ages.​

Answers

Answered by moonsearth9
0

Answer:

Their present ages are

A= 20 years , B= 15 years

Step-by-step explanation:

Let present age of B be x

so, present age of A = x+5

5 years ago

age of A = X+5-5 =x

age of B= x-5

Their ratio = 3:2

i e

A/B= 3/2

x/x-5= 3/2

2x= 3(x-5)

2x= 3x-15

15=3x-2x

15= x

therefore x = 15

therefore B's age is 15 years and

A's age is x+5 = 20 years

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