Math, asked by Xeyahaider, 2 months ago

The age of A is five years more than that of B. 5 years ago, the ratio of their ages was 3:2. The present age of A is​

Answers

Answered by dhruvagarwa006
2

Answer:

The age of A is five years more than that of B. Five years ago, the ratio of their ages was 3:2. What are their present ages?

Answer: The age of A is 20 years and the age of B is 15 years.

Solution:

Method 1:

Suppose that the current age of B = x

So current age of A = x+5

5 years ago age of A would have been = x+5–5 = x

5 years ago age of B would have been = x-5

As per question…

x/(x-5) = 3/2

2x = 3x-15

3x-2x = 15

x = 15

The current age of B= 15

So current age of A = 15+5 = 20

Answered by genius150809
1

let age of b five years ago be 2x

now it will be 2x+5

age of a five years ago be 3x

now it is 3x+5

it is given that

3x+5=2x+5+5

3x+5=2x+10

x=5

age of a 5 yrs ago=3x=15

now it is 15+5=20yrs

so ans is 20

hope it helps

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