Math, asked by MAMT1234, 1 year ago

the age of a is five years more than that of b .5 years ago, the ratio of their ages was 3:2 find the present ages


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Answers

Answered by Anonymous
72
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⭐ Let the age of b be x years.
⭐ Then, age of a = (x+5) years.

5 years ago,
⭐ Age of b = (x-5) years.
⭐ Age of a = (x+5-5) years = x years.

⭐ Also, the ratio is given 3:2 which means 3/2.

So, according to the problem, we get :

 \frac{x}{x - 5} = \frac{3}{2}

=> 3x - 15 = 2x
=> x = 15 \: \: years
⭐ So, Present age of b = x years = 15 years.
⭐ Present age of a = (x+5) years = (15+5) years = 20 years

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MAMT1234: thank you
Answered by jiya9614
21

Answer:

Let the age of b be x years.

Then, age of a = (x+5) years.

5 years ago,

Age of b = (x-5) years.

Age of a = (x+5-5) years = x years.

Also, the ratio is given 3:2 which means 3/2.

So, according to the problem, we get :

\frac{x}{x - 5} = \frac{3}{2}x−5x=23

=> 3x - 15 = 2x=>3x−15=2x

=> x = 15 \: \: years=>x=15years

So, Present age of b = x years = 15 years.

Present age of a = (x+5) years = (15+5) years = 20 years

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