Math, asked by sudeshyadav2286, 1 month ago

the age of a is five years more than that of b five years ago the ratio of their ages was 3 ratio 2 find their present ages​

Answers

Answered by ALPHAPANDEY
2

Answer:

20

Step-by-step explanation:

A = B + 5

A - 5/B - 5 = 3/2

2A - 3B = -5

2B + 10 - 3B = -5

-B = -15

B = 15

A = 15 + 5

= 20

Answered by AshutoshPriyadarshan
2

Answer:

Here is your answer.

Step-by-step explanation:

Let the age of A be x years

and the age of B = (x - 5) years

Age of A 5 years ago = (x - 5) years

and age of B 5 years ago = (x - 5 - 5) years

= (x - 10) years

ATQ,

 \frac{(x - 5)}{(x - 10)} =  \frac{3}{2}  \\  =  > 2(x - 5) = 3(x - 10) \\  =  > 2x - 10 = 3x - 30 \\  =  > x = 20

So, Present age of A = x years = 20 years

and Present age of B = (x - 5) years = 15 years

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