The age of A is one-third the age of B.after 15 years,the age of A will be half the age of B.Find their present ages.
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The age of A =1/3 B.
After 15 years the age of A and B would be (A+15) and (B+15).
According the problem ,
(A+15) = (B+15)/2
Further solving the above equation and substituting A =1/3 B.
B/3+15 = (B+15)/2
(B+45)/3 = (B+15)/2
2(B+45) = 3(B+15)
2B+90=3B+45
3B-2B= 90–45
Therefore B=45.
A=1/3 of B i.e 1/3*45=15.
So age of A=15 and B = 45.
After 15 years the age of A and B would be (A+15) and (B+15).
According the problem ,
(A+15) = (B+15)/2
Further solving the above equation and substituting A =1/3 B.
B/3+15 = (B+15)/2
(B+45)/3 = (B+15)/2
2(B+45) = 3(B+15)
2B+90=3B+45
3B-2B= 90–45
Therefore B=45.
A=1/3 of B i.e 1/3*45=15.
So age of A=15 and B = 45.
nithishgaming:
Thanks!
Answered by
0
A=15 years B=45 years
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