the age of a man 7 years ago was 7 times the age of the son father's age after 3 years will be three times the age of the son find their present ages
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Let present age of father = x
" ". " of son = y
Seven yrs ago ,
x-7= 7(y-7) ...........(1)
After three yrs ,
x+3 =(y+3)3.........(2)
now , you can solve further by equating both equations .
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sajjadullah:
I can not solve it please help me
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