Question

the age of a man 7 years ago was seven times the age of his son.father ,s age after 3 years will be three times the age of the son.find there presnt age.

Answer 1

✨HOLA...!!!✨

ANSWER:-

The age of a man 7 years ago was 7 times the age of his son.

So, let their ages 7 years ago be x and 7x.

Father's age after 3 years will be three times the age of the son.

Father's age after 3 years will be three times the age of the son.3 years from now is 10 years after 7 years ago. So in 3 years their ages will be x+10 and 7x+10.

As, it is given that after 3 years from the present age of the father , his age will become three times the son's age.

Therefore,

7x+10=3 (x+10)

Solving it to get x,

➡7x+10=3x+30

➡7x-3x=30-10

➡4x=20

➡x=20÷4

➡x=5

Hence, the present age of the son and the father becomes ...

Present age of father :-

7x+7

=7 (5)+7

=35+7

=⭐42 years⭐

Present age of son :-

x+7

=5+7=

⭐12 years⭐

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