Question

The age of a man and his daughter differ by 23 years the sum of their ages is 41.
Find the mans age.

Please answer fast my exam is in 14 hours and 53 minutes

Answer 1

Let the age of the man be x

The age of the daughter be y

Sum of ages = 41

i.e, x+y = 41

Difference of ages = 23

i.e., x-y=23

Adding the two equations, we get

x+y+x-y = 41+23

2x = 64

x = 32

Answer 2

Given : The age of a man and the age of his daughter differ by 23 years and the sum of their ages is 41 years.

Need To Find : The age of the man.

⠀⠀⠀⠀⠀_____________________

${\underline{\boldsymbol{ \pink{According \: to \: the \: question :}}}}$

❍Let age of daughter be "x" years.

Then age of man = (x + 23)

$\sf{x + (x + 23) = 41}$

$\sf{x + x + 23 = 41}$

$\sf{2x + 23 = 41}$

$\sf{2x = 41 - 23}$

$\sf{2x = 18}$

$\sf{x = 9}$

$\sf{x + 23=9+23=32 \ years.}$

Therefore,

$\sf{Age \ of \ man \ is \ }$ ${\textsf{\textbf{\pink{32 years.}}}}$