Math, asked by devanshu2837, 11 hours ago

The age of a man is 24 years more than his son. In two years, the father’s age will be twice that of his son. Then the present age of his son is:
A) 18 years B) 21 years C) 22 years D) 24 years

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Answers

Answered by ImperialGladiator
23

Answer:

C) 22 years

Explanation:

Given,

The age of a man is 24 years more than his son.

If we say his son is x years.

Then, man's age would be (x + 24) years.

After two years

  • Son's age = (x + 2) years.
  • Man's age = (x + 24) + 2 = (x + 26) years.

According to the question,

Man is twice the son's age :-

 \rm \implies \: (x + 26) = 2(x + 2)

 \rm \implies \: x + 26= 2x + 4

 \rm \implies \: 26 - 4 = 2x - x

 \rm \implies \: 22 = x

Present age of son is 22 years

Answered by hmangla41
0

Answer:

Answer:

C) 22 years

Explanation:

Given,

The age of a man is 24 years more than his son.

If we say his son is x years.

Then, man's age would be (x + 24) years.

After two years

Son's age = (x + 2) years.

Man's age = (x + 24) + 2 = (x + 26) years.

According to the question,

Man is twice the son's age :-

\rm \implies \: (x + 26) = 2(x + 2)⟹(x+26)=2(x+2)

\rm \implies \: x + 26= 2x + 4⟹x+26=2x+4

\rm \implies \: 26 - 4 = 2x - x⟹26−4=2x−x

\rm \implies \: 22 = x⟹22=x

∴ Present age of son is 22 years

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