Math, asked by devanshu2837, 1 month ago

The age of a man is 24 years more than his son. In two years, the father’s age will be twice that of his son. Then the present age of his son is:
A) 18 years B) 21 years C) 22 years D) 24 years

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Answers

Answered by s1274himendu3564

Solution

After 2 years, father's age become (X+24+2) years and Son's age will be (X+2). Or, X = 22 years. Son's present age = 22 years.

Answered by devanshu1234321

The age of a man is 24 years more than his son. In two years, the father’s age will be twice that of his son. Then the present age of his son is:

A) 18 years B) 21 years C) 22 years D) 24 years

Let the age of son= x years

then the age of father=x+24 years

In two years,

Son age=x+2

Father age=x+26

A.T.Q

=> (x + 24) + 2 = 2(x + 2)

=> x + 26 = 2x + 4

So, x = 22

So the present age of son is 22 years

Hence opt-[c] is the required answer