Question

: The age of a man is 24 years more than his son. In two years, the father’s age will be twice that of his son. Then the present age of his son is:
A) 18 years B) 21 years C) 22 years D) 24 years

Answer 1

Answer:

c is correct

Let the present age of his son be X years.

So, present age of his father = X+24 (as he is 24 years older than his son)

After 2 years, father's age become (X+24+2) years and Son's age will be (X+2).

Now, according to question,

X+24+2 = 2*(X +2)

Or, X = 22 years.

Son's present age = 22 years.

Answer 2

Given : The age of a man is 24 years more than his son. In two years, the father’s age will be twice that of his son.

To Find : The present age of his son?

ㅤㅤ━━━━━━━━━━━━━━

❍ Let us assume that, the present age of his son is 'x'. Then, the man's present age = x + 24. In two years :

↠ Age of his son = x + 2

↠ Age of the man = x + 24 + 2 = x + 26

$\boldsymbol{\underline{According \: to \: the \: question,}}$

$\sf{ \mapsto \: x + 26 = 2(x + 2) }$

$\sf{ \mapsto \: x + 26 = 2x + 4}$

$\sf{ \mapsto \: 26 - 4 = 2x - x}$

$\pink{\sf{ \mapsto \: x = 22}}$

Hence, the present age of his son is 22 years.

ㅤ

So, option (C) 22 years is correct. ✓

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Verification :

$\tt{ \mapsto \: x + 26 = 2(x + 2) }$

❐ Substituting x = 22, we get

$\sf{ \mapsto \: 22 + 26 = 2(22 + 2) }$

$\sf{ \mapsto \: 48 = 44 + 4}$

$\sf{ \mapsto \: 48 = 48}$

$\color{navy}{\sf{ \mapsto \: LHS = RHS}}$

Hence, verified. ✓