The age of a man is 27 years more than the age of his son. If the sum of their ages is 47 years, find the age of the son and his father.
Answers
Answered by
21
Let age of sin be x
Then,father's age=x+27
A.T.Q
x+27+x=47
2x=20
x=10
Hence, son's age is 10 years
And father's age=x+27
=10+27=37
HOPE THIS HELPS U OUT
MARK AS BRAINLIEST
Then,father's age=x+27
A.T.Q
x+27+x=47
2x=20
x=10
Hence, son's age is 10 years
And father's age=x+27
=10+27=37
HOPE THIS HELPS U OUT
MARK AS BRAINLIEST
dhruvanandsingh:
Pls Mark as BRAINLIEST
Answered by
17
let the age of the Son be X
then age of the man =27+x
given
sumof their ages=47
so x+27+x=47
2x+27 =47
2x= 47-27
2x= 20
x =20 ÷ 2=10
therefore age of son= 10 and father 10+27 =37. ANSWER
then age of the man =27+x
given
sumof their ages=47
so x+27+x=47
2x+27 =47
2x= 47-27
2x= 20
x =20 ÷ 2=10
therefore age of son= 10 and father 10+27 =37. ANSWER
Similar questions