Question

the age of a man is 3 time of his son 6 years ago the man was 7 time old as his son at that time present age of son?​

Answer 1

Explanation:

Let the son's present age be x. Then the man's age is 3x.

Six years ago, son's age would be (x-6) and the man's age would be (3x-6).

But it is given that the man was 7 times the age of his son 6 years ago.

So from the given details, the following equation can be formed:

$\frac{3x-6}{x-6}=\frac{7}{1}$

==> $3x-6=7(x-6)$ [transposing x - 6 to the RHS]

==> $3x - 6 = 7x - 42$ [opening brackets]

==> $-6+42=7x-3x$ [bringing like terms to the same side]

==> $4x=36$ ==> $x=\frac{36}{4}$ [transposing 4]

∴ $x=9\:years$

Hence, the present age of the son is 9 years.

Answer: 9 years

I hope this helps. :D