Question

The age of a
man
is 3 times
son
the
age of his
a hence his
and
5 years
double
the
age will
age of his
son
Find the
present
age of the
man.​

Answer 1

Step-by-step explanation:

Let the sum of ages of two sons be x years

Age of man = 3xyears

After 5 years age of the man =(3x+5)years

Sum of ages of two sons =(x+10)years

Given, (3x+5)=2(x+10)

⇒ (3x+5)=2x+20

⇒ x=15

Hence 3x=3(15)=45

∴ Present age of father is 45years.

Answer 2

Correct Question :

The age of a man is 3 times the age his son .After 5 years his age will be double the age of his son. Find the present age of the man .

Given :

• The age of a man is 3 times the age his son .
• After 5 years his age will be double the age of his son.

To Find :

• Present Age of the Man .

Solution :

$\longmapsto\tt{Let\:Present\:Age\:of\:the\:son\:be=x}$

As Given that the age of a man is 3 times the age his son . So ,

$\longmapsto\tt{Age\:of\:Man=3x}$

After 5 years :

$\longmapsto\tt{Age\:of\:Son=x+5}$

$\longmapsto\tt{Age\:of\:Man=3x+5}$

A.T.Q :

$\longmapsto\tt{2(x+5)=3x+5}$

$\longmapsto\tt{2x+10=3x+5}$

$\longmapsto\tt{2x-3x=5-10}$

$\longmapsto\tt{-1x=-5}$

$\longmapsto\tt\bf{x=5}$

Value of x is 5 ...

Therefore :

$\longmapsto\tt{Present\:Age\:of\:Man=3(5)}$

$\longmapsto\tt\bf{15\:yrs}$