Question

The age of a man is 4 times of his son. Five years ago, the man was nine times old as his son was at that time. The present age of man is?
A)

Answer 1

Let the age of son be x and age of father be 4x.

Five years ago ,

    Age of son = x-5

    Age of father = 4x-5

According to the question ,

 4x-5 = 9(x-5)

 4x-5 = 9x - 45

 9x-4x = 45-5

      5x = 40

       x = 8

Age of man = 32 years