Question

The age of a man is 4 times of his son. Five years ago, the man was nine times old as his son was at that time. The present age of man is?

Don't answer if you don't know!!

Answer 1

Let the son's age be x year,

Then man age's be 4x year.

5 year ago, their ages are (x - 5) years

And (4x - 5) yr, respectively.

(4x - 5) = 9 (x - 5)

= 5x = 40

= x = 8 years

Therefore:

Present age of the man = 4x

= 4 x 8

= 32 Years

• Hence, the present age of the man is 32 years.

Answer 2

Given

• The age of a man is 4 times of his son.
• 5 years ago, the man was nine times old as his son was at that time.

Explanation

Let the age of the son be x and the age of the man be 4x Respectively.

5 years ago,

• Son's age be = (x - 5) years
• Man's age be = (4x - 5) years

$\\ \maltese \ {\pmb{\underline{\sf{ According \ to \ Question: }}}} \\ \\ \colon\implies{\sf{ 9(x-5) = (4x-5) }} \\ \\ \\ \colon\implies{\sf{ 9x - 45 = 4x - 5 }} \\ \\ \\ \colon\implies{\sf{ 9x-4x = -5+45 }} \\ \\ \\ \colon\implies{\sf{ 5x = 40 }} \\ \\ \\ \colon\implies{\sf{ x = \cancel{ \dfrac{40}{5} } }} \\ \\ \\ \colon\implies{\sf{ x = 8 }}$

Hence,

• Present age of Son = 8 years
• Present age of Man = 4×8 = 32 years.