Question

The age of a man is 4 times that of his son. Five year ago the man was nine times as old as his son was at that time. The present age of the man is??​

Answer 1

$\huge \underline \mathbb {SOLUTION:-}$

AnsWer:

• The present age of the man is 32 Years.

Given:

• The age of a man is 4 times that of his son. Five year ago the man was nine times as old as his son was at that time

Need To Find:

• The present age of the man is = ?

Explanation:

Let the son's age be x year,

Then man age's be 4x year.

5 year ago, their ages are (x - 5) years

And (4x - 5) yr, respectively.

According to the given condition:

➠ (4x - 5) = 9 (x - 5)

➠ 5x = 40

➠ x = 8 years

Therefore:

Present age of the man = 4x

➠ 4 × 8

➠ 32 Years

• Hence, the present age of the man is 32 years.

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Answer 2

Given

The age of a man is 4 times that of his son. Five year ago the man was nine times as old as his son was at that time.

To find

The present age of the man

Solution

Let the son age be x then his father age be 4x

After five years ago

Father age = (4x - 5)

Son age = (x - 5)

According to the given condition

=> 4x - 5 = 9(x - 5)

=> 4x - 5 = 9x - 45

=> 45 - 5 = 9x - 4x

=> 40 = 5x

=> x = 40/5 = 8

${\boxed{\bf{Required\:value\:of\:x=8\:year}}}$

Hence, Son age = x = 8 year

Father age = 4x = 8 × 4 = 32 year