Question

The age of a man is 4 times that of his son. Five years ago, the man was five times as old as his son was at that time. Find the present age of the son ?​

Answer 1

Let the age of son be =x
So father’s age is 4x
Five years ago age of son =x-5
Age of father: 5(x-5)




So after equating it we get
4x-5=5(x-5)
So we get
4x-5 =5x-25
So
X=20
So age of son is 20 years.

Answer 2

Given :

• The age of a man is 4 times that of his son.

• Five years ago, the man was five times as old as his son was at that time.

To find :

• Find the present age of the son = ?

Step-by-step explanation :

Let the age of son be x

Let his father's age be 4x

Five years ago, age of son = x - 5

Five years ago, age of father = 4x - 5

5 years ago the man was five times as old as his son = 5(x - 5)

According to the question,

➮ 4x - 5 = 5(x - 5)

➮ 4x - 5 = 5x - 25

➮ 4x - 5x = -25 + 5

➮ x = 20

Therefore, We know that the value of x = 20

Hence,

Present age of son is x = 20 years

Therefore, the present age of son = 20 years.