The age of a man is 9 times as old as his son in 2010. in 2011, his age is equal to the square of his son's age. what is the age of the man in 2013 ?
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Suppose the age of a son in 2010 is x years.
So according to the question,
Father's age in 2010 is 9x years.
Now,son's age in 2011 = x+1 years.
&
Father's age in 2011 = 9x+1 years.
But according to the question,
(9x+1) = (x+1)^2
=> 9x+1 = x^2 + 2x + 1
=> x^2 + 2x - 9x = 0
=> x^2 - 7x = 0
=> (x)(x-7) = 0
Since age can not be zero,
x=7
So the father's age in 2010 = 9x =9×7=63 years
●So the age of father in 2013 = 63+3 = 66 years.
●●●Hope It Helps●●●
Suppose the age of a son in 2010 is x years.
So according to the question,
Father's age in 2010 is 9x years.
Now,son's age in 2011 = x+1 years.
&
Father's age in 2011 = 9x+1 years.
But according to the question,
(9x+1) = (x+1)^2
=> 9x+1 = x^2 + 2x + 1
=> x^2 + 2x - 9x = 0
=> x^2 - 7x = 0
=> (x)(x-7) = 0
Since age can not be zero,
x=7
So the father's age in 2010 = 9x =9×7=63 years
●So the age of father in 2013 = 63+3 = 66 years.
●●●Hope It Helps●●●
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