The age of a man is three
times the age of his son. After
10 years, the age of the man
will be double that of the son.
Assuming the age of the son
to be x, find their present
ages.
*
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Answer:
age of son = X
age of father = 3X
after 10 yrs.
age f son = x+10
" " man= 3x+10
now, 3x+10 = 2(x+10) ..........(frm d qutn)
3x+10=2x+20
3x-2x=20-10
x =10= age f son
3x=3*10 = 30 = age of man
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