Question

The age of a man is three
times the age of his son. After
10 years, the age of the man
will be double that of the son.
Assuming the age of the son
to be x, find their present
ages.
*​

Answer 1

Answer:

age of son =  X

age of  father = 3X

after 10 yrs.

age f son = x+10

"    "    man= 3x+10

now,   3x+10 = 2(x+10) ..........(frm d qutn)

          3x+10=2x+20

          3x-2x=20-10

           x =10= age f son

           3x=3*10 = 30 = age of man

Step-by-step explanation: