Question

The age of a man is three times the sum of ages of his two children and five years hence his age will be double the sum of their ages . Find his present age ​

Answer 1

Answer :-

Let the sum of ages of two sons be x years

Age of man = 3xyears

After 5 years age of the man =(3x+5)years

Sum of ages of two sons =(x+10)years

Given, (3x+5)=2(x+10)

⇒  (3x+5)=2x+20

⇒  x=15

Hence 3x=3(15)=45

∴  Present age of father is 45years.