The age of a man is three times the sum of the ages of his two sons
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Step-by-step explanation:
Let the Man's age be M years.
Let the Sum of ages of both Children be C years.
Man's age M = 3 C = 3 times the sum of sons' ages.
M+5 = Man's age after 5 years = 2 (C+10) ,as each child's age increases by 5 years. and their sum increases by 10 years.
So, M = 3 C
M + 5 = 2 (C +10) = 2 C + 20
Substitute 1st equation in the 2nd.
3 C + 5 = 2 C + 20
C = 15 years
M = 45 years
The mans' age now is 45 years and sum of children's age is 15 years now.
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