Question

The age of a man is three times the sum of the
ages of his two sons. Five years hence, his age
will be double of the sum of the ages of his
sons. The father's present age is
a) 40 years
b) 45 years
c) 50 years
d) 55 years

Answer 1

Answer:

45 years is your answer

Explanation:

Assume the ages of sons as x and y

Therefore Fathers age will be 3(x+y)

Five years hence,

Sons ages will be x+5 and y+5

Fathers age will be 2(x+y+10)

But fathers age is also equal to 3(x+y)+5

on solving the above two equation you will get x+y=15 ...

thus fathers age is thrice of it which is 45

Answer 2

Let the sum of ages of two sons be x years

Age of man = 3x years

After 5 years age of the man = (3x + 5) years

Sum of ages of two sons = (x + 10) years

Given, (3x + 5) = 2(x + 10)

⇒ (3x + 5) = 2x + 20

⇒ x = 15

Hence 3x = 3(15) = 45

Thus the age of the man(father) is 45 years(option b)