Question

The age of a man is three times the sum of the ages of his two sons and 5 years hence his age will be double
the sum of their ages. Find the present age of the man:
(a) 60
(b) 52
(c) 51
(d) 50​

Answer 1

Present age of man is 45 years.

Step-by-step explanation:

Given :-

• The age of a man is three times the sum of the ages of his two sons.
• 5 years hence, his age will be double the sum of their ages.

To find :-

• Present age of man.

Solution :-

Let ,

• Man's present age = x years
• Present age of 1st son = y years
• Present age of 2nd son = z years

${\underline{\sf{According\:to\:the\:1st\: condition:-}}}$

• The age of a man is three times the sum of the ages of his two sons.

➪ x = 3(y+z)

➪ y+z = x/3 ..................(i)

${\underline{\sf{According\:to\:the\:2nd\: condition:-}}}$

• 5 years hence, his age will be double the sum of their ages

5 years hence,

• Man's age = (x+5) years
• Age of 1st son = (y+5) years
• Age of 2nd son = (z+5) years

➪ x+5 = 2[(y+5)+(z+5)]

➪ x+5 = 2(y+z+10)

• [ put y+z = x/3 from eq (i)]

➪ x+5 = 2(x/3 + 10)

➪ x+5 = 2x/3 + 20

➪ x - 2x/3 = 20-5

➪ x/3 = 15

➪ x = 45

† Present age of man is 45 years.

________________

Answer 2

Answer:

I think the answer should be 45

Step-by-step explanation:

let the age of two sons be x

then the father's age would be 3x

five years hence,the father's age would be double the age of two sons which means

the age of two sons would be x+10

then the father's age would be 3x+5

3 X + 5 is equal to 2 (X + 10)

when you further solve it

it will give x=15

then the father's age would be 3x i.e. 3*15=45

the present age of the father would be 45 years