The age of a man is three times the sum of the ages of his two sons. Five years later his age will be double the sum of the ages of his sons. What is the present age of the father?
(3) 48 years
(4) 54 years
(1) 42 years
(2) 45 years
Answers
Answered by
3
Answer:
The present age of a father is equal to the sum of the ages of his 5 children. 12 years hence, the sum of the ages of his children will be twice the age of their father.
Step-by-step explanation:
Let the sum of ages of two sons be x years
Age of man = 3xyears
After 5 years age of the man =(3x+5)years
Sum of ages of two sons =(x+10)years
Given, (3x+5)=2(x+10)
⇒ (3x+5)=2x+20
⇒ x=15
Hence 3x=3(15)=45
∴ Present age of father is 45years.
Answered by
7
Answer:
The given equation is
f(x)=x3+3x2−5x+1=0
Replace x by 2x in the above equation to get the desired equation.
The required equation is
f(2x)=(2x)3+3(2x)2−5(2x)+1=0
=8x3+43x2−25x+1=0
On solving the equation, we get
x3+6x2−20x+8=0
Step-by-step explanation:
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