Math, asked by maheshwarinandini564, 5 months ago

The age of a man is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than three times the age of his son. Find their present ages.​

Answers

Answered by Sayan9561
1

Answer:

Son=4 yrs

Father= 32yrs

Step-by-step explanation:

Let age of father be x and son be y.

Then,

x =2 y ^{2}

x + 8 = 3(y + 8) + 4

Now solve.

Answered by PharohX
2

Answer:

  • Age of man is 32 year and age of son is 4 year.

Step-by-step explanation:

GIVEN INFORMATION :-

  • The age of a man is twice the square of the age of his son.
  • Eight years hence, the age of the man will be 4 years more than three times the age of his son.

TO FIND :-

  • Present age of man and his son.

SOLUTION :-

Let the present age of son is x years

Then

↝ According to First information -

The age of a man is twice the square of the age of his son.

 \sf \: The \:  \:  age \:  \:  of  \:  \: a  \:  \: man = twice \:  \: the \:  \: square \: of \:  \: son

 \sf \: The \:  \:  age  \:  \: of  \:  \: a  \:  \: man = 2 {x}^{2}

↝ According to Second Information.

 \sf \: ↝ \: 8 \: years \: hence \:  -

 \sf \: Age \:  \:  of  \:  \: son = (x + 8) \: year

 \sf \: Age  \: of \: man \:  = (2 {x}^{2}  + 8) \:  \: year

The age of the man will be 4 years more than three times the age of his son.

 \sf \: the \:  \:  age \:  \:  of  \:  \: the \:  \:  man = 4 \: year \: more \: than \:  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \: three \: times \: the \: son

 \sf \: (2 {x}^{2}  + 8) = 4 + 3(x + 8)

 \sf \implies \: 2 {x}^{2}  + 8 = 3x + 24 + 4

 \sf \implies \: 2 {x}^{2}  + 8 = 3x + 28

 \sf \implies \: 2 {x}^{2}   - 3x  -  20

 \sf \implies \: 2 {x}^{2}   - 8x  + 5x -  20

 \sf \implies \: 2x(x  - 4)  + 5(x -  4)

 \sf \implies \: (x  - 4)(2x + 5)

Hence

 \sf \implies \: x = 4 \:  \: or \:  \:  \frac{ - 5}{2}  \\

but age can't be negative

 \sf \:  hence \:  \:  \boxed{ \sf x = 4}

Age of son =x = 4 years

 \sf \: Age  \:  \: of  \:  \: man = 2 {x}^{2}

 \sf \: Age  \:  \: of  \:  \: man = 2( {4}^{2})

 \sf \: Age  \:  \: of  \:  \: man = 32 \: year

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