Question

The age of a mother and a daughter are 31 and 7 years respectively the number of years in which the mother age will be three by two times that of the daughters age is

Answer 1

$\textbf{Answer}$

$\textbf{Age of mother = 31 years}$

$\textbf{Age of daughter = 7 years}$

Lets suppose that after X years,
mother's age will be three by two times that of daughter's age.

$\textbf{After X years,}$
Age of Mother = (31 + X) years
Age of Daughter = (7 + X) years

$\textbf{According to the question,}$
(31 + X) = 3/2 (7 + X)

=> 62 + 2X = 21 + 3X

=> 3X - 2X = 62 - 21

=> X = 41

$\textbf{Lets verify the value of X=41,}$
Mother's age after 41 years = 31+41 = 72

Daughter's age after 41 years = 7+41 = 48

Ratio of ages of mother and daughter is
72 : 48 = 3 : 2 $\textbf{which satisfies the statement}$ that after 41 years, mother's age will be three by two times of the daughter's age.

$\textbf{So the answer is 41 years.}$

$\textbf{Hope It Helps}$
$\textbf{Thanks}$

Answer 2

$\textbf{Answer :}$

The current age of the mother is 31 years and that of the daughter is 7 years

Let us take that after x years, the mother's age will be 3/2 times of the daughter's age

After x years, the mother will be (31 + x) years old and the daughter will be (7 + x) years old

By the given condition,

31 + x = 3/2 (7 + x)

or, 2 (31 + x) = 3 (7 + x)

or, 62 + 2x = 21 + 3x

or, 3x - 2x = 62 - 21

or, x = 41

Therefore, in $\textbf{41 years}$, the required conditions will be fulfilled.

#$\textbf{MarkAsBrainliest}$