Question

The age of a mother is twice the square of the age of her daughter eight years from now the age of mother will be 4 years more than three times the age of her daughter find present ages

Answer 1

Step-by-step explanation:

Son’s present age is 4 years and mothers present age is 32 years. The math is as follows:

Suppose

Son’s present age = x years

Mother’s present age = y years

Then we have

y=2x^2

y+8=3(x+8) +4

Substituting the value of y from equation 1 in equation 2,

2x^2 +8=3(x +8) +4

or, 2x^2-3x-20=0

or, (x-4)(2x+5)=0

So

Either x=4

Or x= -5/2

Since age can't be negative

Hence x=4

And y= 2×4^2=32

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Answer 2

Answer: Present age of daughter is 4

Present age of mother is 32

Step-by-step explanation:

Please refer the given picture to get the detailed answer