Math, asked by mhatreseema62, 4 days ago

The age of Ajay and his younger brother Vijay are in the ratio of 7:4. Six years ago, their age were in the ratio of 4:1. Find their present age​

Answers

Answered by presentmoment
2

explanation is provided below,

Step-by-step explanation:

Let the age of Ajay be "A" and Vijay be "V".

A:V=7:4 ---(1)

Six years ago, there age was,

A-6:V-6=4:1

A-6= 4(V-6)

A-6=4V-24

A=4V-18 ---(2)

Substituting the value (2) in (1)

4V-18:V=7:4

by cross mutiplication

16V-72=7V

9V=72

V= 8 years

A= 4V-18

giving

A= 14 years

So the present ages will be

Answered by raj12a257
0

Answer:

Step-by-step explanation:

let us assume that present age of Ajay and vijay are 7x and 4x respectively

then six years ago their age will be as follows

7x - 6 for ajay and 4x - 6 for Vijay

. ' . 7x - 6 /4x - 6 = 4 / 1

therefore the will come as x equals

after calculations

so the present age of Ajay will be 7 X 2 which is 14 yrs

And of Vijay will be 4 X 2 = 8 years.



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