The age of Alice is 5 years more than the age of her sister Jessica . After 5 years the ratio of their ages will be 3:2 .Find their present ages.
Linear equations chapterp
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hi..
i dont know ratio prop. to much so this is lil confusing...
i mean i know but not too good
equatins is easy
equations
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Heya !!!
This is your answer.
Let the age of Alice be x.
Therefore, age of Jesicca = x - 5.
Age of Alice after five yrs = x + 5.
and, Age of Jessica after 5 years = x - 5 + 5 = x
It is given that ratio of their age will be 3:2 after 5 years.
So,
(x+5)/x = 3/2
Cross Multiplying...
3x = 2 (x+5)
3x = 2x + 10
x = 10.
Now, the age of Alice is 10 yrs and her sister's age is x-5 = 10 yrs.
Hope It Helps
This is your answer.
Let the age of Alice be x.
Therefore, age of Jesicca = x - 5.
Age of Alice after five yrs = x + 5.
and, Age of Jessica after 5 years = x - 5 + 5 = x
It is given that ratio of their age will be 3:2 after 5 years.
So,
(x+5)/x = 3/2
Cross Multiplying...
3x = 2 (x+5)
3x = 2x + 10
x = 10.
Now, the age of Alice is 10 yrs and her sister's age is x-5 = 10 yrs.
Hope It Helps
please dont report
I'm editing
done
Sisters age 5/10?
no
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