Math, asked by vgspinners, 4 months ago

The age of Arjun is five years more than, that of Babita. Five years ago, the ratio of their age was 3:2. Find their ages after 5 years??

Answers

Answered by dualadmire
3

Given:

The age of Arjun is five years more than, that of Babita.

Five years ago, the ratio of their age was= 3:2

To find:

Their ages after 5 years.

Solution:

Let the present age of Arjun and Babita be 5+x and x respectively.

Five years ago their age would be x and x-5.

And the ratio will be 3:2, so

x/ (x-5) = 3/2

2x = 3(x-5)

2x = 3x- 5

x = 5 years.

Therefore their present age of Arjun and Babita will be 10 years and 5 years respectively.

After 5 years their age will be 15 years and 10 years.

Therefore the age of Arjun after 5 years will be 15 years and that of Babita will be 10 years.

Answered by pulakmath007
4

SOLUTION

GIVEN

  • The age of Arjun is five years more than, that of Babita

  • Five years ago, the ratio of their age was 3:2

TO DETERMINE

Their ages after 5 years

EVALUATION

Here it is given that Five years ago, the ratio of ages of Arjun and Babita was 3 : 2

Let 5 years age of Arjun and Babita was 3x years and 2x years respectively

So the present age of Arjun and Babita is 3x + 5 years and 2x + 5 years respectively

So by the given condition

 \sf{(3x + 5) - (2x + 5) = 5}

 \sf{ \implies \: 3x + 5 - 2x  -  5 = 5}

 \sf{ \implies \: x= 5}

So present age of Arjun and Babita is 20 years and 15 years respectively

Hence after 5 years age of Arjun and Babita will be 25 years and 20 years respectively

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