The age of b is 38 years less than twice the age of a and the age of b is 19 years more than the half of the age of a. What is the sum of the ages of a and b?
Answers
Answered by
0
Let present age of the son = x. Ten present age of the father = 3x + 3
After three years, age of the son = (x+3) and age of the father = (3x+3+3) = (3x+6)
Given that (3x+6) = 10 + 2(x+3)
3x + 6 = 10 + 2x + 6
x = 10
Present age of the father = 3x+3 = 3*10 + 3 = 33
2. father's age when her brother was born = 38+4 = 42
mother's age when her brother was born = 36
difference between the ages of her parents = 42 -36 = 6
3. Let present age of B = x and present age of A = (x+9)
After 10 years, age of A = x+9+10 = x +19
Before 10 years, age of B = (x-10)
Given that (x+19) = 2(x-10)
x + 19 = 2x - 20
x = 39
present age of B = 39
After three years, age of the son = (x+3) and age of the father = (3x+3+3) = (3x+6)
Given that (3x+6) = 10 + 2(x+3)
3x + 6 = 10 + 2x + 6
x = 10
Present age of the father = 3x+3 = 3*10 + 3 = 33
2. father's age when her brother was born = 38+4 = 42
mother's age when her brother was born = 36
difference between the ages of her parents = 42 -36 = 6
3. Let present age of B = x and present age of A = (x+9)
After 10 years, age of A = x+9+10 = x +19
Before 10 years, age of B = (x-10)
Given that (x+19) = 2(x-10)
x + 19 = 2x - 20
x = 39
present age of B = 39
Similar questions