Question

the age of deepak and sandeep are in 8years ago their age where in the ratio 7:13. find their present age​

Answer 1

Answer:

Step-by-step explanation:

So eight years back they were 5x-8 years and 7x-8 years old

Therefore 5x-8=7y & 7x-8=13y

5x-7y=8 ..........(1)

7x-13y=8..........(2)

(1)×7 = 35x-49y=56........(3)

(2)×5=35x-65y=40........(4)

Subtract (4) from (3)

We get y=1

Now for x

5x-8=7

5x=15

So,x=3

Their present ages are 5x=15 &7x=21