Math, asked by arpitsahu57, 11 months ago

The age of father 10 year ago was thrice the age of his son. Ten year hence father age will be twice that of his son. The ratio of there present ages is

Answers

Answered by amitagnidev
4

Answer:

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Answered by Anonymous
36

Answer:

Let the age of Father and son be x and 3x years respectively.

After Ten years,

Age of father = x + 10 years

Age of son = 3x + 10

According to Question now,

(3x + 10) + 10 = 2(x + 10) + 10

3x + 20 = 2(x + 20)

3x + 20 = 2x + 40

3x - 2x = 40 - 20

x = 20 years.

Therefore, Required ratio :

(3x + 10) : (x + 10)

3(20) + 10 : 20 + 10

60 + 10 : 30

70 : 30

7 : 3

Therefore, the required ratio is 7:3.

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