Math, asked by tanmayhada, 9 months ago

The age of father 10 years ago was thrice the age of his son .Ten years later ,the father's age will be twice that of his son .The ratio of their present ages is?
Proper explanation for Brainliest​

Answers

Answered by kartik2507
0

Answer:

ratio of the ages of father and son

7 : 3

father's age = 70

son's age = 30

Step-by-step explanation:

let the present age of father be x

let the present age of son be y

10 years ago father was thrice the age of son

x - 10 = 3(y - 10)

x - 10 = 3y - 30

x - 3y = -30 + 10

x - 3y = -20. equ (1)

10 years later father will be twice of the son's age

x + 10 = 2(y + 10)

x + 10 = 2y + 20

x - 2y = 20 - 10

x - 2y = 10 equ (2)

subtract (1) - (2)

y = 30

substitute y = 30 in equ (1)

x - 3y = -20

x - 3(30) = -20

x - 90 = -20

x = -20 + 90

x = 70

therefore father's present age = x = 70

son's present age = y = 30

ratio of the ages

70 : 30

7 : 3

hope you get your answer

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