The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. What is the ratio of their present ages? Plaese help me to solve the problem.
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let the present age of father be x years and son be years.
first case:. (x-10)=3(y-10)
(x-10)=3y-30
x-3y=-20-----------1)
Second case:
(x+10)=2(y+10)
x+10=2y+20
x-2y=10-----------2)
on solving we get,x=30years. and y=10years
ratio: 3:1 Ans
first case:. (x-10)=3(y-10)
(x-10)=3y-30
x-3y=-20-----------1)
Second case:
(x+10)=2(y+10)
x+10=2y+20
x-2y=10-----------2)
on solving we get,x=30years. and y=10years
ratio: 3:1 Ans
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