Math, asked by ianushkagupta9784, 1 year ago

The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
A.5 : 2
B.7 : 3
C.9 : 2
D.13 : 4

Answers

Answered by Dbangde
4

the ans is 7:3

because

father =x(present age)

son=y

than, 10year ago


x-10=(y-10)3

x-3y=-20 ....(1)

10yr hence

x+10=(y+10)2

x-2y=10 .....(2)

to (1)and(2)

x=70 and y=30

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