Question

The age of father 10 years ago was thrice the age of his son ten years hence,fathers age will be twice thatof his son.The ratio of their present ages is:

Answer 1

Solution:

Let son's age 10 years ago be x.

Father's age 10 years ago = 3x

2(x+20) = (3x+20)

x = 20

10 years ago, father's age = 60 years and son's age = 20 years

Ratio of their present age = 70:30 = 7:3

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