Question

The age of father 20 years ago was the age of his son now. Now the father's
age is twice the age of his son. Find the present age of father and son.
(a) 70,30
(b) 40,20
(c) 50,10
(d) 80,30​

Answer 1

Answer:

Step-by-step explanation:

let son be x years

father = 2x

..

20 years ago

son = x-20

father = 2x-20

..

2x-20=12*(x-20)

2x-20 = 12x -240

add 20 to both sides

2x = 12x-240+20

2x=12x-220

add -12x to both sides

2x-12x= 12x-12x-220

-12x+2x= -240+20

-10x= -220

divide by -10

x= -220/-10

x=22 son's age

Father's age = 2*22 = 44 years