Math, asked by abhinav401486, 1 year ago


The age of father 3 years ago was 7 tim
the age of his son. At present the father's
five times that of his son. what are the
present age of son and father?

Answers

Answered by hemalathakalyani
0

Answer: son age is 9 years and father age is 45 years.

Step-by-step explanation:

Let father age be X and son age be y

 current age be X = 5Y

  three years ago , X - 3 = 7(Y - 3)

                                5Y - 3 = 7Y - 21   ( put X = 5Y)

                                2Y = 18

                                  Y = 9

son age is 9 and father age is 45 ( 5*9)

Answered by Anonymous
11

Answer:

Let the present age son be x years and present age of father be 5x years.

According to Question now,

➳ 7(x - 3) = 5x - 3

➳ 7x - 21 = 5x - 3

➳ 7x - 5x = -3 + 21

➳ 2x = 18

➳ x = 18/2

➳ x = 9 years

Therefore,

Present age of son = x = 9 years

Present age of father = 5x = 45 years.

Similar questions