Question

the age of father 8 years ago was 8 times the age of his son. after 10 years the age of the father will be twice the age of the son find their present ages​?
please solve. no spam. or else report.​ said correct answer. no wrong ans.
please answer fast. pls​

Answer 1

Answer:

Correct option is B)

Let the present age of the son be x.

Let the father's present age be y.

One year ago, y−1=8(x−1)

⇒y−1=8x−8

⇒y=8x−7

Now applying the condition, we get

(8x−7)=x

2

⇒x

2

−8x+7=0

⇒(x−1)(x−7)=0

⇒x=1 or x=7

Hence, the present age of son is either 1 year or 7 years.

I hope you mark a me Brainleit

Answer 2

Answer:

Let son's age = x

Two years ago son's age= x-2.

His Father's age at that time = 3(x-2).

Present age of Father = 3x-6+2=3x-4

Two years hence father's age=3x-4+2=3x-2.

Two years hence son's age = x+2.

Given :-5*(x+2)=2*(3x-2)

5x + 10= 6x - 4

10+4=6x-5x

14=x

SON'S PRESENT AGE : 14 years.

FATHER'S PTESENT AGE: 38 years.

Step-by-step explanation:

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